Base | Representation |
---|---|
bin | 10011001101000111101… |
… | …010111101100100101101 |
3 | 11200011112011101120221221 |
4 | 103031013222331210231 |
5 | 133110330343420321 |
6 | 2450142125223341 |
7 | 164230550562556 |
oct | 23150752754455 |
9 | 4604464346857 |
10 | 1319757404461 |
11 | 469784715631 |
12 | 193940101b51 |
13 | 975b6452a02 |
14 | 47c3b56132d |
15 | 244e3720e41 |
hex | 13347abd92d |
1319757404461 has 2 divisors, whose sum is σ = 1319757404462. Its totient is φ = 1319757404460.
The previous prime is 1319757404419. The next prime is 1319757404473. The reversal of 1319757404461 is 1644047579131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1151221702500 + 168535701961 = 1072950^2 + 410531^2 .
It is a cyclic number.
It is not a de Polignac number, because 1319757404461 - 27 = 1319757404333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1319757404399 and 1319757404408.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1319757404401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659878702230 + 659878702231.
It is an arithmetic number, because the mean of its divisors is an integer number (659878702231).
Almost surely, 21319757404461 is an apocalyptic number.
It is an amenable number.
1319757404461 is a deficient number, since it is larger than the sum of its proper divisors (1).
1319757404461 is an equidigital number, since it uses as much as digits as its factorization.
1319757404461 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2540160, while the sum is 52.
The spelling of 1319757404461 in words is "one trillion, three hundred nineteen billion, seven hundred fifty-seven million, four hundred four thousand, four hundred sixty-one".
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