Base | Representation |
---|---|
bin | 100111010101011… |
… | …0000100110100001 |
3 | 10101222111102002112 |
4 | 1032222300212201 |
5 | 10200334110334 |
6 | 334544325105 |
7 | 44464246421 |
oct | 11652604641 |
9 | 3358442075 |
10 | 1319831969 |
11 | 618013325 |
12 | 30a013795 |
13 | 18058ca81 |
14 | c7404481 |
15 | 7ad0b4ce |
hex | 4eab09a1 |
1319831969 has 2 divisors, whose sum is σ = 1319831970. Its totient is φ = 1319831968.
The previous prime is 1319831951. The next prime is 1319831971. The reversal of 1319831969 is 9691389131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 982007569 + 337824400 = 31337^2 + 18380^2 .
It is an emirp because it is prime and its reverse (9691389131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1319831969 - 220 = 1318783393 is a prime.
It is a super-2 number, since 2×13198319692 = 3483912852788833922, which contains 22 as substring.
Together with 1319831971, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1319831939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659915984 + 659915985.
It is an arithmetic number, because the mean of its divisors is an integer number (659915985).
Almost surely, 21319831969 is an apocalyptic number.
It is an amenable number.
1319831969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1319831969 is an equidigital number, since it uses as much as digits as its factorization.
1319831969 is an evil number, because the sum of its binary digits is even.
The product of its digits is 314928, while the sum is 50.
The square root of 1319831969 is about 36329.4917250434. The cubic root of 1319831969 is about 1096.9147621714.
The spelling of 1319831969 in words is "one billion, three hundred nineteen million, eight hundred thirty-one thousand, nine hundred sixty-nine".
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