Base | Representation |
---|---|
bin | 111101011101111010… |
… | …0000010011111101111 |
3 | 110121201022021202211021 |
4 | 1322323310002133233 |
5 | 4130313444444413 |
6 | 140350122035011 |
7 | 12352040326045 |
oct | 1727364023757 |
9 | 417638252737 |
10 | 131999999983 |
11 | 50a87616785 |
12 | 216ba648a67 |
13 | c5a834bb87 |
14 | 6562d64395 |
15 | 367872618d |
hex | 1ebbd027ef |
131999999983 has 2 divisors, whose sum is σ = 131999999984. Its totient is φ = 131999999982.
The previous prime is 131999999953. The next prime is 132000000001. The reversal of 131999999983 is 389999999131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131999999983 - 217 = 131999868911 is a prime.
It is a super-3 number, since 3×1319999999833 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131999999933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65999999991 + 65999999992.
It is an arithmetic number, because the mean of its divisors is an integer number (65999999992).
Almost surely, 2131999999983 is an apocalyptic number.
131999999983 is a deficient number, since it is larger than the sum of its proper divisors (1).
131999999983 is an equidigital number, since it uses as much as digits as its factorization.
131999999983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 344373768, while the sum is 79.
The spelling of 131999999983 in words is "one hundred thirty-one billion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred eighty-three".
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