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13200002019431 is a prime number
BaseRepresentation
bin1100000000010101110101…
…1011100111000001100111
31201201220111211120210220122
43000011131123213001213
53212232101004110211
644023555221552155
72531445232616063
oct300053533470147
951656454523818
1013200002019431
11422a0a9020147
1215922b9b7565b
137499a7533806
14338c524b0aa3
1517d567da96db
hexc015d6e7067

13200002019431 has 2 divisors, whose sum is σ = 13200002019432. Its totient is φ = 13200002019430.

The previous prime is 13200002019341. The next prime is 13200002019437. The reversal of 13200002019431 is 13491020000231.

Together with previous prime (13200002019341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13200002019431 - 222 = 13199997825127 is a prime.

It is a super-2 number, since 2×132000020194312 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13200002019431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13200002019437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600001009715 + 6600001009716.

It is an arithmetic number, because the mean of its divisors is an integer number (6600001009716).

Almost surely, 213200002019431 is an apocalyptic number.

13200002019431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200002019431 is an equidigital number, since it uses as much as digits as its factorization.

13200002019431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 13200002019431 its reverse (13491020000231), we get a palindrome (26691022019662).

The spelling of 13200002019431 in words is "thirteen trillion, two hundred billion, two million, nineteen thousand, four hundred thirty-one".