Base | Representation |
---|---|
bin | 11000100101100100… |
… | …00000110001000101 |
3 | 1021001221010120210022 |
4 | 30102302000301011 |
5 | 204013200031432 |
6 | 10021453504525 |
7 | 645052111121 |
oct | 142262006105 |
9 | 37057116708 |
10 | 13200002117 |
11 | 5664069a65 |
12 | 26847a2145 |
13 | 1324959c53 |
14 | 8d314c581 |
15 | 523cabb12 |
hex | 312c80c45 |
13200002117 has 2 divisors, whose sum is σ = 13200002118. Its totient is φ = 13200002116.
The previous prime is 13200002083. The next prime is 13200002129. The reversal of 13200002117 is 71120000231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12959317921 + 240684196 = 113839^2 + 15514^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13200002117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13200002095 and 13200002104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13200002177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600001058 + 6600001059.
It is an arithmetic number, because the mean of its divisors is an integer number (6600001059).
Almost surely, 213200002117 is an apocalyptic number.
It is an amenable number.
13200002117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200002117 is an equidigital number, since it uses as much as digits as its factorization.
13200002117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 17.
Adding to 13200002117 its reverse (71120000231), we get a palindrome (84320002348).
The spelling of 13200002117 in words is "thirteen billion, two hundred million, two thousand, one hundred seventeen".
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