Base | Representation |
---|---|
bin | 11110000000110110101011… |
… | …001101011101011000101100 |
3 | 122022101002100002102120000110 |
4 | 132000312223031131120230 |
5 | 114300142202144341030 |
6 | 1144424002044300020 |
7 | 36542456406116346 |
oct | 3600665315353054 |
9 | 568332302376013 |
10 | 132000102340140 |
11 | 39071a24598741 |
12 | 1297a607241610 |
13 | 588673009c248 |
14 | 2484ba648c296 |
15 | 103d95b53e1b0 |
hex | 780dab35d62c |
132000102340140 has 48 divisors (see below), whose sum is σ = 369600790406400. Its totient is φ = 35199979304640.
The previous prime is 132000102340121. The next prime is 132000102340153. The reversal of 132000102340140 is 41043201000231.
132000102340140 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 75873825 + ... + 77594055.
It is an arithmetic number, because the mean of its divisors is an integer number (7700016466800).
Almost surely, 2132000102340140 is an apocalyptic number.
132000102340140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132000102340140 is an abundant number, since it is smaller than the sum of its proper divisors (237600688066260).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132000102340140 is a wasteful number, since it uses less digits than its factorization.
132000102340140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2999142 (or 2999140 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 132000102340140 its reverse (41043201000231), we get a palindrome (173043303340371).
The spelling of 132000102340140 in words is "one hundred thirty-two trillion, one hundred two million, three hundred forty thousand, one hundred forty".
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