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13200101301133 is a prime number
BaseRepresentation
bin1100000000010110001101…
…0110010101101110001101
31201201220202202101211210201
43000011203112111232031
53212232301413114013
644024013125533501
72531450546530105
oct300054326255615
951656682354721
1013200101301133
11422a14a070a3a
121592327274291
137499c1c85396
14338c61756205
1517d57196b3dd
hexc0163595b8d

13200101301133 has 2 divisors, whose sum is σ = 13200101301134. Its totient is φ = 13200101301132.

The previous prime is 13200101301113. The next prime is 13200101301139. The reversal of 13200101301133 is 33110310100231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7045345650249 + 6154755650884 = 2654307^2 + 2480878^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13200101301133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13200101301133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13200101301139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600050650566 + 6600050650567.

It is an arithmetic number, because the mean of its divisors is an integer number (6600050650567).

Almost surely, 213200101301133 is an apocalyptic number.

It is an amenable number.

13200101301133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200101301133 is an equidigital number, since it uses as much as digits as its factorization.

13200101301133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13200101301133 its reverse (33110310100231), we get a palindrome (46310411401364).

The spelling of 13200101301133 in words is "thirteen trillion, two hundred billion, one hundred one million, three hundred one thousand, one hundred thirty-three".