Base | Representation |
---|---|
bin | 1100000000010110001101… |
… | …0110010101111110101011 |
3 | 1201201220202202101220020202 |
4 | 3000011203112111332223 |
5 | 3212232301413132222 |
6 | 44024013125542415 |
7 | 2531450546533142 |
oct | 300054326257653 |
9 | 51656682356222 |
10 | 13200101302187 |
11 | 422a14a071808 |
12 | 1592327274a0b |
13 | 7499c1c859c7 |
14 | 338c61756759 |
15 | 17d57196b892 |
hex | c0163595fab |
13200101302187 has 2 divisors, whose sum is σ = 13200101302188. Its totient is φ = 13200101302186.
The previous prime is 13200101302127. The next prime is 13200101302189. The reversal of 13200101302187 is 78120310100231.
13200101302187 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13200101302187 is a prime.
Together with 13200101302189, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13200101302189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600050651093 + 6600050651094.
It is an arithmetic number, because the mean of its divisors is an integer number (6600050651094).
Almost surely, 213200101302187 is an apocalyptic number.
13200101302187 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200101302187 is an equidigital number, since it uses as much as digits as its factorization.
13200101302187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
The spelling of 13200101302187 in words is "thirteen trillion, two hundred billion, one hundred one million, three hundred two thousand, one hundred eighty-seven".
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