132001043220037 has 2 divisors, whose sum is σ = 132001043220038. Its totient is φ = 132001043220036.

The previous prime is 132001043219987. The next prime is 132001043220061. The reversal of 132001043220037 is 730022340100231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80783532817156 + 51217510402881 = 8987966^2 + 7156641^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132001043220037 is a prime.

It is a super-2 number, since 2×132001043220037² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132001043219987 and 132001043220014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132001043220077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66000521610018 + 66000521610019.

It is an arithmetic number, because the mean of its divisors is an integer number (66000521610019).

Almost surely, 2^{132001043220037} is an apocalyptic number.

It is an amenable number.

132001043220037 is a deficient number, since it is larger than the sum of its proper divisors (1).

132001043220037 is an equidigital number, since it uses as much as digits as its factorization.

132001043220037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 132001043220037 its reverse (730022340100231), we get a palindrome (862023383320268).

The spelling of 132001043220037 in words is "one hundred thirty-two trillion, one billion, forty-three million, two hundred twenty thousand, thirty-seven".