Base | Representation |
---|---|
bin | 11110000000110111100110… |
… | …101100110101010101011011 |
3 | 122022101011220122111021210121 |
4 | 132000313212230311111123 |
5 | 114300201223201423233 |
6 | 1144424245100454111 |
7 | 36542523215503432 |
oct | 3600674654652533 |
9 | 568334818437717 |
10 | 132001100420443 |
11 | 39072396a201a1 |
12 | 1297a84554a337 |
13 | 588685bab66c7 |
14 | 2484c5cc5a119 |
15 | 103d9b8e9192d |
hex | 780de6b3555b |
132001100420443 has 2 divisors, whose sum is σ = 132001100420444. Its totient is φ = 132001100420442.
The previous prime is 132001100420411. The next prime is 132001100420471. The reversal of 132001100420443 is 344024001100231.
It is a strong prime.
It is an emirp because it is prime and its reverse (344024001100231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132001100420443 - 25 = 132001100420411 is a prime.
It is not a weakly prime, because it can be changed into another prime (132001100420743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66000550210221 + 66000550210222.
It is an arithmetic number, because the mean of its divisors is an integer number (66000550210222).
Almost surely, 2132001100420443 is an apocalyptic number.
132001100420443 is a deficient number, since it is larger than the sum of its proper divisors (1).
132001100420443 is an equidigital number, since it uses as much as digits as its factorization.
132001100420443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 132001100420443 its reverse (344024001100231), we get a palindrome (476025101520674).
The spelling of 132001100420443 in words is "one hundred thirty-two trillion, one billion, one hundred million, four hundred twenty thousand, four hundred forty-three".
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