13200123401251 has 2 divisors, whose sum is σ = 13200123401252. Its totient is φ = 13200123401250.

The previous prime is 13200123401197. The next prime is 13200123401281. The reversal of 13200123401251 is 15210432100231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13200123401251 - 2⁷ = 13200123401123 is a prime.

It is not a weakly prime, because it can be changed into another prime (13200123401281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600061700625 + 6600061700626.

It is an arithmetic number, because the mean of its divisors is an integer number (6600061700626).

Almost surely, 2^{13200123401251} is an apocalyptic number.

13200123401251 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200123401251 is an equidigital number, since it uses as much as digits as its factorization.

13200123401251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 13200123401251 its reverse (15210432100231), we get a palindrome (28410555501482).

The spelling of 13200123401251 in words is "thirteen trillion, two hundred billion, one hundred twenty-three million, four hundred one thousand, two hundred fifty-one".