Base | Representation |
---|---|
bin | 1100000000010110010100… |
… | …1100010000001001100100 |
3 | 1201201220211220120020120201 |
4 | 3000011211030100021210 |
5 | 3212232332321230200 |
6 | 44024020152240244 |
7 | 2531451403336156 |
oct | 300054514201144 |
9 | 51656756506521 |
10 | 13200132211300 |
11 | 422a165563231 |
12 | 15923356a0084 |
13 | 7499c84b8718 |
14 | 338c658c0ad6 |
15 | 17d574524c6a |
hex | c0165310264 |
13200132211300 has 72 divisors (see below), whose sum is σ = 28883953669760. Its totient is φ = 5236055395200.
The previous prime is 13200132211261. The next prime is 13200132211363. The reversal of 13200132211300 is 311223100231.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4715461 + ... + 6973939.
Almost surely, 213200132211300 is an apocalyptic number.
13200132211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13200132211300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14441976834880).
13200132211300 is an abundant number, since it is smaller than the sum of its proper divisors (15683821458460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200132211300 is a wasteful number, since it uses less digits than its factorization.
13200132211300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2258981 (or 2258974 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 13200132211300 its reverse (311223100231), we get a palindrome (13511355311531).
The spelling of 13200132211300 in words is "thirteen trillion, two hundred billion, one hundred thirty-two million, two hundred eleven thousand, three hundred".
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