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132001331020397 is a prime number
BaseRepresentation
bin11110000000110111110100…
…011100100000001001101101
3122022101012111201101222110122
4132000313310130200021231
5114300202211220123042
61144424324015214325
736542532015535466
oct3600676434401155
9568335451358418
10132001331020397
11390724a5103373
121297a8aa8173a5
1358868977c5a97
142484c81725d6d
15103d9ce3427d2
hex780df472026d

132001331020397 has 2 divisors, whose sum is σ = 132001331020398. Its totient is φ = 132001331020396.

The previous prime is 132001331020387. The next prime is 132001331020469. The reversal of 132001331020397 is 793020133100231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79277191443076 + 52724139577321 = 8903774^2 + 7261139^2 .

It is a cyclic number.

It is not a de Polignac number, because 132001331020397 - 212 = 132001331016301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132001331020327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66000665510198 + 66000665510199.

It is an arithmetic number, because the mean of its divisors is an integer number (66000665510199).

Almost surely, 2132001331020397 is an apocalyptic number.

It is an amenable number.

132001331020397 is a deficient number, since it is larger than the sum of its proper divisors (1).

132001331020397 is an equidigital number, since it uses as much as digits as its factorization.

132001331020397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20412, while the sum is 35.

The spelling of 132001331020397 in words is "one hundred thirty-two trillion, one billion, three hundred thirty-one million, twenty thousand, three hundred ninety-seven".