Base | Representation |
---|---|
bin | 1100000000010110010101… |
… | …0000001011111000100011 |
3 | 1201201220211222111121222201 |
4 | 3000011211100023320203 |
5 | 3212232333102224103 |
6 | 44024020230314031 |
7 | 2531451415162252 |
oct | 300054520137043 |
9 | 51656758447881 |
10 | 13200133242403 |
11 | 422a1660a7988 |
12 | 1592335ab8917 |
13 | 7499c8789b43 |
14 | 338c65aac799 |
15 | 17d57467a51d |
hex | c016540be23 |
13200133242403 has 2 divisors, whose sum is σ = 13200133242404. Its totient is φ = 13200133242402.
The previous prime is 13200133242377. The next prime is 13200133242419. The reversal of 13200133242403 is 30424233100231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13200133242403 - 25 = 13200133242371 is a prime.
It is not a weakly prime, because it can be changed into another prime (13200133242203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600066621201 + 6600066621202.
It is an arithmetic number, because the mean of its divisors is an integer number (6600066621202).
Almost surely, 213200133242403 is an apocalyptic number.
13200133242403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200133242403 is an equidigital number, since it uses as much as digits as its factorization.
13200133242403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 13200133242403 its reverse (30424233100231), we get a palindrome (43624366342634).
The spelling of 13200133242403 in words is "thirteen trillion, two hundred billion, one hundred thirty-three million, two hundred forty-two thousand, four hundred three".
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