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1320014320214 = 21934737218953
BaseRepresentation
bin10011001101010110111…
…111000001001001010110
311200012012001211021010012
4103031112333001021112
5133111342131221324
62450223424000222
7164240120410232
oct23152677011126
94605161737105
101320014320214
114698a67421a7
121939b2160072
1397627747175
1447c6371b5c2
152450b06e20e
hex13356fc1256

1320014320214 has 8 divisors (see below), whose sum is σ = 2084233137240. Its totient is φ = 625269941136.

The previous prime is 1320014320199. The next prime is 1320014320217. The reversal of 1320014320214 is 4120234100231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1320014320214.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320014320217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17368609439 + ... + 17368609514.

It is an arithmetic number, because the mean of its divisors is an integer number (260529142155).

Almost surely, 21320014320214 is an apocalyptic number.

1320014320214 is a deficient number, since it is larger than the sum of its proper divisors (764218817026).

1320014320214 is a wasteful number, since it uses less digits than its factorization.

1320014320214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34737218974.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1320014320214 its reverse (4120234100231), we get a palindrome (5440248420445).

The spelling of 1320014320214 in words is "one trillion, three hundred twenty billion, fourteen million, three hundred twenty thousand, two hundred fourteen".

Divisors: 1 2 19 38 34737218953 69474437906 660007160107 1320014320214