1320020132441 has 2 divisors, whose sum is σ = 1320020132442. Its totient is φ = 1320020132440.

The previous prime is 1320020132401. The next prime is 1320020132443. The reversal of 1320020132441 is 1442310200231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1048516608841 + 271503523600 = 1023971^2 + 521060^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320020132441 is a prime.

Together with 1320020132443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1320020132443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660010066220 + 660010066221.

It is an arithmetic number, because the mean of its divisors is an integer number (660010066221).

Almost surely, 2^{1320020132441} is an apocalyptic number.

It is an amenable number.

1320020132441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320020132441 is an equidigital number, since it uses as much as digits as its factorization.

1320020132441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1320020132441 its reverse (1442310200231), we get a palindrome (2762330332672).

The spelling of 1320020132441 in words is "one trillion, three hundred twenty billion, twenty million, one hundred thirty-two thousand, four hundred forty-one".