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1320021422413 = 4728085562179
BaseRepresentation
bin10011001101010111011…
…010000111000101001101
311200012012120012002111121
4103031113122013011031
5133111400441004123
62450224240120541
7164240234650321
oct23152732070515
94605176162447
101320021422413
114698aa753191
121939b4606151
1397629062a55
1447c64649981
152450b9c375d
hex1335768714d

1320021422413 has 4 divisors (see below), whose sum is σ = 1348106984640. Its totient is φ = 1291935860188.

The previous prime is 1320021422399. The next prime is 1320021422441. The reversal of 1320021422413 is 3142241200231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1320021422413 - 25 = 1320021422381 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320021422453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14042781043 + ... + 14042781136.

It is an arithmetic number, because the mean of its divisors is an integer number (337026746160).

Almost surely, 21320021422413 is an apocalyptic number.

It is an amenable number.

1320021422413 is a deficient number, since it is larger than the sum of its proper divisors (28085562227).

1320021422413 is an equidigital number, since it uses as much as digits as its factorization.

1320021422413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28085562226.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1320021422413 its reverse (3142241200231), we get a palindrome (4462262622644).

The spelling of 1320021422413 in words is "one trillion, three hundred twenty billion, twenty-one million, four hundred twenty-two thousand, four hundred thirteen".

Divisors: 1 47 28085562179 1320021422413