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13200224120403 = 34793618610783
BaseRepresentation
bin1100000000010110101010…
…1010110110111001010011
31201201221002022111201011120
43000011222222312321103
53212233024333323103
644024033234213323
72531453600502555
oct300055252667123
951657068451146
1013200224120403
11422a202428971
121592360424243
13749a115585c8
14338c73ba74d5
1517d57c62c253
hexc016aab6e53

13200224120403 has 8 divisors (see below), whose sum is σ = 17974773270528. Its totient is φ = 8612912191944.

The previous prime is 13200224120399. The next prime is 13200224120411. The reversal of 13200224120403 is 30402142200231.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13200224120403 - 22 = 13200224120399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13200224120483) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46809305251 + ... + 46809305532.

It is an arithmetic number, because the mean of its divisors is an integer number (2246846658816).

Almost surely, 213200224120403 is an apocalyptic number.

13200224120403 is a deficient number, since it is larger than the sum of its proper divisors (4774549150125).

13200224120403 is an equidigital number, since it uses as much as digits as its factorization.

13200224120403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93618610833.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13200224120403 its reverse (30402142200231), we get a palindrome (43602366320634).

The spelling of 13200224120403 in words is "thirteen trillion, two hundred billion, two hundred twenty-four million, one hundred twenty thousand, four hundred three".

Divisors: 1 3 47 141 93618610783 280855832349 4400074706801 13200224120403