Base | Representation |
---|---|
bin | 1100000000010110101110… |
… | …1000010010011111101000 |
3 | 1201201221010102210212110200 |
4 | 3000011223220102133220 |
5 | 3212233042444133412 |
6 | 44024035011312200 |
7 | 2531454154413525 |
oct | 300055350223750 |
9 | 51657112725420 |
10 | 13200240224232 |
11 | 422a210527a16 |
12 | 15923658ab660 |
13 | 749a149a64b9 |
14 | 338c75d9a14c |
15 | 17d57dc5d9dc |
hex | c016ba127e8 |
13200240224232 has 96 divisors (see below), whose sum is σ = 36442949088000. Its totient is φ = 4315611830400.
The previous prime is 13200240224231. The next prime is 13200240224239. The reversal of 13200240224232 is 23242204200231.
13200240224232 is a `hidden beast` number, since 1 + 3 + 2 + 0 + 0 + 2 + 402 + 24 + 232 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 13200240224196 and 13200240224205.
It is not an unprimeable number, because it can be changed into a prime (13200240224231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6825607 + ... + 8543382.
It is an arithmetic number, because the mean of its divisors is an integer number (379614053000).
Almost surely, 213200240224232 is an apocalyptic number.
13200240224232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13200240224232 is an abundant number, since it is smaller than the sum of its proper divisors (23242708863768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200240224232 is a wasteful number, since it uses less digits than its factorization.
13200240224232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15369231 (or 15369224 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 27.
Adding to 13200240224232 its reverse (23242204200231), we get a palindrome (36442444424463).
The spelling of 13200240224232 in words is "thirteen trillion, two hundred billion, two hundred forty million, two hundred twenty-four thousand, two hundred thirty-two".
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