Base | Representation |
---|---|
bin | 1100000000010110101111… |
… | …0110111000100011010010 |
3 | 1201201221010201000020121121 |
4 | 3000011223312320203102 |
5 | 3212233044434101010 |
6 | 44024035225312454 |
7 | 2531454232056664 |
oct | 300055366704322 |
9 | 51657121006547 |
10 | 13200244050130 |
11 | 422a212700415 |
12 | 159236703572a |
13 | 749a15715a47 |
14 | 338c766b4534 |
15 | 17d57e2673da |
hex | c016bdb88d2 |
13200244050130 has 8 divisors (see below), whose sum is σ = 23760439290252. Its totient is φ = 5280097620048.
The previous prime is 13200244050127. The next prime is 13200244050137. The reversal of 13200244050130 is 3105044200231.
It can be written as a sum of positive squares in 2 ways, for example, as 13174235714689 + 26008335441 = 3629633^2 + 161271^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13200244050095 and 13200244050104.
It is not an unprimeable number, because it can be changed into a prime (13200244050137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 660012202497 + ... + 660012202516.
Almost surely, 213200244050130 is an apocalyptic number.
13200244050130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13200244050130 is a deficient number, since it is larger than the sum of its proper divisors (10560195240122).
13200244050130 is a wasteful number, since it uses less digits than its factorization.
13200244050130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1320024405020.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 13200244050130 its reverse (3105044200231), we get a palindrome (16305288250361).
The spelling of 13200244050130 in words is "thirteen trillion, two hundred billion, two hundred forty-four million, fifty thousand, one hundred thirty".
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