Base | Representation |
---|---|
bin | 111101011101111110… |
… | …1010110011110101110 |
3 | 110121201110212210110021 |
4 | 1322323331112132232 |
5 | 4130320111104014 |
6 | 140350250232354 |
7 | 12352100144104 |
oct | 1727375263656 |
9 | 417643783407 |
10 | 132002441134 |
11 | 50a88a33863 |
12 | 216bb4256ba |
13 | c5a89c5045 |
14 | 65633dbc74 |
15 | 3678a59624 |
hex | 1ebbf567ae |
132002441134 has 4 divisors (see below), whose sum is σ = 198003661704. Its totient is φ = 66001220566.
The previous prime is 132002441107. The next prime is 132002441189. The reversal of 132002441134 is 431144200231.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 132002441099 and 132002441108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33000610282 + ... + 33000610285.
It is an arithmetic number, because the mean of its divisors is an integer number (49500915426).
Almost surely, 2132002441134 is an apocalyptic number.
132002441134 is a deficient number, since it is larger than the sum of its proper divisors (66001220570).
132002441134 is an equidigital number, since it uses as much as digits as its factorization.
132002441134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66001220569.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 132002441134 its reverse (431144200231), we get a palindrome (563146641365).
The spelling of 132002441134 in words is "one hundred thirty-two billion, two million, four hundred forty-one thousand, one hundred thirty-four".
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