Base | Representation |
---|---|
bin | 1100000000010110111111… |
… | …0111100101110101000111 |
3 | 1201201221022101122011002000 |
4 | 3000011233313211311013 |
5 | 3212233214201010310 |
6 | 44024050031520343 |
7 | 2531456010054234 |
oct | 300055767456507 |
9 | 51657271564060 |
10 | 13200311344455 |
11 | 422a247693664 |
12 | 15923856890b3 |
13 | 749a26647b81 |
14 | 338c815d078b |
15 | 17d58510b4c0 |
hex | c016fde5d47 |
13200311344455 has 32 divisors (see below), whose sum is σ = 24847644888000. Its totient is φ = 6626038634496.
The previous prime is 13200311344447. The next prime is 13200311344471. The reversal of 13200311344455 is 55444311300231.
13200311344455 is a `hidden beast` number, since 1 + 3 + 200 + 3 + 1 + 1 + 3 + 4 + 445 + 5 = 666.
It is not a de Polignac number, because 13200311344455 - 23 = 13200311344447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2875882530 + ... + 2875887119.
It is an arithmetic number, because the mean of its divisors is an integer number (776488902750).
Almost surely, 213200311344455 is an apocalyptic number.
13200311344455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13200311344455 is a deficient number, since it is larger than the sum of its proper divisors (11647333543545).
13200311344455 is a wasteful number, since it uses less digits than its factorization.
13200311344455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5751769680 (or 5751769674 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 13200311344455 its reverse (55444311300231), we get a palindrome (68644622644686).
The spelling of 13200311344455 in words is "thirteen trillion, two hundred billion, three hundred eleven million, three hundred forty-four thousand, four hundred fifty-five".
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