Base | Representation |
---|---|
bin | 10011001101010111111… |
… | …111011101101110000111 |
3 | 11200012020020121120200102 |
4 | 103031113333131232013 |
5 | 133111410442330341 |
6 | 2450225230034315 |
7 | 164240414122514 |
oct | 23152777355607 |
9 | 4605206546612 |
10 | 1320031214471 |
11 | 4699052310a2 |
12 | 1939b794899b |
13 | 9762b0b0a78 |
14 | 47c65a7830b |
15 | 2450c7a9c9b |
hex | 13357fddb87 |
1320031214471 has 2 divisors, whose sum is σ = 1320031214472. Its totient is φ = 1320031214470.
The previous prime is 1320031214377. The next prime is 1320031214479. The reversal of 1320031214471 is 1744121300231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1320031214471 - 218 = 1320030952327 is a prime.
It is a super-3 number, since 3×13200312144713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320031214479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660015607235 + 660015607236.
It is an arithmetic number, because the mean of its divisors is an integer number (660015607236).
Almost surely, 21320031214471 is an apocalyptic number.
1320031214471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320031214471 is an equidigital number, since it uses as much as digits as its factorization.
1320031214471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 29.
The spelling of 1320031214471 in words is "one trillion, three hundred twenty billion, thirty-one million, two hundred fourteen thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •