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13200321502541 is a prime number
BaseRepresentation
bin1100000000010111000001…
…1110010101110101001101
31201201221100002202020100102
43000011300132111311031
53212233224301040131
644024051033340445
72531456162312525
oct300056036256515
951657302666312
1013200321502541
11422a2523a1578
121592388b67725
13749a28793684
14338c82ab6685
1517d585e661cb
hexc0170795d4d

13200321502541 has 2 divisors, whose sum is σ = 13200321502542. Its totient is φ = 13200321502540.

The previous prime is 13200321502531. The next prime is 13200321502547. The reversal of 13200321502541 is 14520512300231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12350691066025 + 849630436516 = 3514355^2 + 921754^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200321502541 - 210 = 13200321501517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13200321502547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600160751270 + 6600160751271.

It is an arithmetic number, because the mean of its divisors is an integer number (6600160751271).

Almost surely, 213200321502541 is an apocalyptic number.

It is an amenable number.

13200321502541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200321502541 is an equidigital number, since it uses as much as digits as its factorization.

13200321502541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 13200321502541 its reverse (14520512300231), we get a palindrome (27720833802772).

The spelling of 13200321502541 in words is "thirteen trillion, two hundred billion, three hundred twenty-one million, five hundred two thousand, five hundred forty-one".