Base | Representation |
---|---|
bin | 1100000000010111000010… |
… | …1001110110101001100011 |
3 | 1201201221100022102120021102 |
4 | 3000011300221312221203 |
5 | 3212233231034124142 |
6 | 44024051222145015 |
7 | 2531456230052423 |
oct | 300056051665143 |
9 | 51657308376242 |
10 | 13200324520547 |
11 | 422a254072a9a |
12 | 1592389b8216b |
13 | 749a292ac288 |
14 | 338c83260483 |
15 | 17d586360532 |
hex | c0170a76a63 |
13200324520547 has 2 divisors, whose sum is σ = 13200324520548. Its totient is φ = 13200324520546.
The previous prime is 13200324520507. The next prime is 13200324520583. The reversal of 13200324520547 is 74502542300231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13200324520547 - 212 = 13200324516451 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13200324520547.
It is not a weakly prime, because it can be changed into another prime (13200324520507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600162260273 + 6600162260274.
It is an arithmetic number, because the mean of its divisors is an integer number (6600162260274).
Almost surely, 213200324520547 is an apocalyptic number.
13200324520547 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200324520547 is an equidigital number, since it uses as much as digits as its factorization.
13200324520547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 38.
Adding to 13200324520547 its reverse (74502542300231), we get a palindrome (87702866820778).
The spelling of 13200324520547 in words is "thirteen trillion, two hundred billion, three hundred twenty-four million, five hundred twenty thousand, five hundred forty-seven".
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