Base | Representation |
---|---|
bin | 111101011110000101… |
… | …1111000010100000101 |
3 | 110121201202001021212111 |
4 | 1322330023320110011 |
5 | 4130322044442413 |
6 | 140350504021021 |
7 | 12352144415641 |
oct | 1727413702405 |
9 | 417652037774 |
10 | 132006249733 |
11 | 50a900a5266 |
12 | 21700761771 |
13 | c5a9729757 |
14 | 6563b0dc21 |
15 | 367905cd3d |
hex | 1ebc2f8505 |
132006249733 has 2 divisors, whose sum is σ = 132006249734. Its totient is φ = 132006249732.
The previous prime is 132006249701. The next prime is 132006249761. The reversal of 132006249733 is 337942600231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114662149924 + 17344099809 = 338618^2 + 131697^2 .
It is a cyclic number.
It is not a de Polignac number, because 132006249733 - 25 = 132006249701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132006249533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66003124866 + 66003124867.
It is an arithmetic number, because the mean of its divisors is an integer number (66003124867).
Almost surely, 2132006249733 is an apocalyptic number.
It is an amenable number.
132006249733 is a deficient number, since it is larger than the sum of its proper divisors (1).
132006249733 is an equidigital number, since it uses as much as digits as its factorization.
132006249733 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 163296, while the sum is 40.
Adding to 132006249733 its reverse (337942600231), we get a palindrome (469948849964).
The spelling of 132006249733 in words is "one hundred thirty-two billion, six million, two hundred forty-nine thousand, seven hundred thirty-three".
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