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132006249733 is a prime number
BaseRepresentation
bin111101011110000101…
…1111000010100000101
3110121201202001021212111
41322330023320110011
54130322044442413
6140350504021021
712352144415641
oct1727413702405
9417652037774
10132006249733
1150a900a5266
1221700761771
13c5a9729757
146563b0dc21
15367905cd3d
hex1ebc2f8505

132006249733 has 2 divisors, whose sum is σ = 132006249734. Its totient is φ = 132006249732.

The previous prime is 132006249701. The next prime is 132006249761. The reversal of 132006249733 is 337942600231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114662149924 + 17344099809 = 338618^2 + 131697^2 .

It is a cyclic number.

It is not a de Polignac number, because 132006249733 - 25 = 132006249701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132006249533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66003124866 + 66003124867.

It is an arithmetic number, because the mean of its divisors is an integer number (66003124867).

Almost surely, 2132006249733 is an apocalyptic number.

It is an amenable number.

132006249733 is a deficient number, since it is larger than the sum of its proper divisors (1).

132006249733 is an equidigital number, since it uses as much as digits as its factorization.

132006249733 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 163296, while the sum is 40.

Adding to 132006249733 its reverse (337942600231), we get a palindrome (469948849964).

The spelling of 132006249733 in words is "one hundred thirty-two billion, six million, two hundred forty-nine thousand, seven hundred thirty-three".