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13201034241001 is a prime number
BaseRepresentation
bin1100000000011001101011…
…1101001110001111101001
31201202000011202220002201011
43000012122331032033221
53212241204231203001
644024245454023521
72531512635430315
oct300063275161751
951660152802634
1013201034241001
11422a588751522
1215925477a7ba1
13749b10342bc9
14338d0d608b45
1517d5c8802d51
hexc019af4e3e9

13201034241001 has 2 divisors, whose sum is σ = 13201034241002. Its totient is φ = 13201034241000.

The previous prime is 13201034240993. The next prime is 13201034241011. The reversal of 13201034241001 is 10014243010231.

13201034241001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11529963536400 + 1671070704601 = 3395580^2 + 1292699^2 .

It is a cyclic number.

It is not a de Polignac number, because 13201034241001 - 23 = 13201034240993 is a prime.

It is not a weakly prime, because it can be changed into another prime (13201034241011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600517120500 + 6600517120501.

It is an arithmetic number, because the mean of its divisors is an integer number (6600517120501).

Almost surely, 213201034241001 is an apocalyptic number.

It is an amenable number.

13201034241001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201034241001 is an equidigital number, since it uses as much as digits as its factorization.

13201034241001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13201034241001 its reverse (10014243010231), we get a palindrome (23215277251232).

The spelling of 13201034241001 in words is "thirteen trillion, two hundred one billion, thirty-four million, two hundred forty-one thousand, one".