Base | Representation |
---|---|
bin | 1100000000011001101011… |
… | …1101001110001111110011 |
3 | 1201202000011202220002201112 |
4 | 3000012122331032033303 |
5 | 3212241204231203021 |
6 | 44024245454023535 |
7 | 2531512635430331 |
oct | 300063275161763 |
9 | 51660152802645 |
10 | 13201034241011 |
11 | 422a588751531 |
12 | 15925477a7bab |
13 | 749b10342c06 |
14 | 338d0d608b51 |
15 | 17d5c8802d5b |
hex | c019af4e3f3 |
13201034241011 has 2 divisors, whose sum is σ = 13201034241012. Its totient is φ = 13201034241010.
The previous prime is 13201034241001. The next prime is 13201034241067. The reversal of 13201034241011 is 11014243010231.
It is a weak prime.
It is an emirp because it is prime and its reverse (11014243010231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13201034241011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201034241001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600517120505 + 6600517120506.
It is an arithmetic number, because the mean of its divisors is an integer number (6600517120506).
Almost surely, 213201034241011 is an apocalyptic number.
13201034241011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201034241011 is an equidigital number, since it uses as much as digits as its factorization.
13201034241011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13201034241011 its reverse (11014243010231), we get a palindrome (24215277251242).
The spelling of 13201034241011 in words is "thirteen trillion, two hundred one billion, thirty-four million, two hundred forty-one thousand, eleven".
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