Base | Representation |
---|---|
bin | 10011001101011100101… |
… | …100000011011111101001 |
3 | 11200012102201212221002222 |
4 | 103031130230003133221 |
5 | 133112041130344033 |
6 | 2450241123003425 |
7 | 164242361651204 |
oct | 23153454033751 |
9 | 4605381787088 |
10 | 1320110012393 |
11 | 469945761147 |
12 | 193a1a209575 |
13 | 9764150cc63 |
14 | 47c7230a93b |
15 | 24514672598 |
hex | 1335cb037e9 |
1320110012393 has 2 divisors, whose sum is σ = 1320110012394. Its totient is φ = 1320110012392.
The previous prime is 1320110012381. The next prime is 1320110012401. The reversal of 1320110012393 is 3932100110231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 874324112809 + 445785899584 = 935053^2 + 667672^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320110012393 - 218 = 1320109750249 is a prime.
It is a super-2 number, since 2×13201100123932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1320110312393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660055006196 + 660055006197.
It is an arithmetic number, because the mean of its divisors is an integer number (660055006197).
Almost surely, 21320110012393 is an apocalyptic number.
It is an amenable number.
1320110012393 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320110012393 is an equidigital number, since it uses as much as digits as its factorization.
1320110012393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 26.
The spelling of 1320110012393 in words is "one trillion, three hundred twenty billion, one hundred ten million, twelve thousand, three hundred ninety-three".
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