Base | Representation |
---|---|
bin | 111101011110001111… |
… | …0000101000000001101 |
3 | 110121202002000122212012 |
4 | 1322330132011000031 |
5 | 4130324310122201 |
6 | 140351154151005 |
7 | 12352233105206 |
oct | 1727436050015 |
9 | 417662018765 |
10 | 132011020301 |
11 | 50a92863486 |
12 | 21702282465 |
13 | c5aa709c84 |
14 | 65645d25ad |
15 | 36796a15bb |
hex | 1ebc78500d |
132011020301 has 2 divisors, whose sum is σ = 132011020302. Its totient is φ = 132011020300.
The previous prime is 132011020283. The next prime is 132011020313. The reversal of 132011020301 is 103020110231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123784348900 + 8226671401 = 351830^2 + 90701^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132011020301 is a prime.
It is a super-2 number, since 2×1320110203012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132011020381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005510150 + 66005510151.
It is an arithmetic number, because the mean of its divisors is an integer number (66005510151).
Almost surely, 2132011020301 is an apocalyptic number.
It is an amenable number.
132011020301 is a deficient number, since it is larger than the sum of its proper divisors (1).
132011020301 is an equidigital number, since it uses as much as digits as its factorization.
132011020301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 132011020301 its reverse (103020110231), we get a palindrome (235031130532).
The spelling of 132011020301 in words is "one hundred thirty-two billion, eleven million, twenty thousand, three hundred one".
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