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1320110240412 = 223110009186701
BaseRepresentation
bin10011001101011100101…
…100111011001010011100
311200012102202022111220010
4103031130230323022130
5133112041210143122
62450241131523220
7164242363621035
oct23153454731234
94605382274803
101320110240412
114699458a7497
12193a1a2b9510
139764158c992
1447c72369a8c
15245146b9e0c
hex1335cb3b29c

1320110240412 has 12 divisors (see below), whose sum is σ = 3080257227656. Its totient is φ = 440036746800.

The previous prime is 1320110240389. The next prime is 1320110240443. The reversal of 1320110240412 is 2140420110231.

It is a tau number, because it is divible by the number of its divisors (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55004593339 + ... + 55004593362.

Almost surely, 21320110240412 is an apocalyptic number.

1320110240412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1320110240412 is an abundant number, since it is smaller than the sum of its proper divisors (1760146987244).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320110240412 is a wasteful number, since it uses less digits than its factorization.

1320110240412 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 110009186708 (or 110009186706 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1320110240412 its reverse (2140420110231), we get a palindrome (3460530350643).

The spelling of 1320110240412 in words is "one trillion, three hundred twenty billion, one hundred ten million, two hundred forty thousand, four hundred twelve".

Divisors: 1 2 3 4 6 12 110009186701 220018373402 330027560103 440036746804 660055120206 1320110240412