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13201110002222 = 26600555001111
BaseRepresentation
bin1100000000011001111101…
…1110001110101000101110
31201202000101001110011120022
43000012133132032220232
53212241333130032342
644024301201522142
72531514545410442
oct300063736165056
951660331404508
1013201110002222
11422a617497aaa
121592569043352
13749b22c4ab2c
14338d196ca822
1517d5d02ba9d2
hexc019f78ea2e

13201110002222 has 4 divisors (see below), whose sum is σ = 19801665003336. Its totient is φ = 6600555001110.

The previous prime is 13201110002191. The next prime is 13201110002237. The reversal of 13201110002222 is 22220001110231.

13201110002222 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13201110002222.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3300277500554 + ... + 3300277500557.

It is an arithmetic number, because the mean of its divisors is an integer number (4950416250834).

Almost surely, 213201110002222 is an apocalyptic number.

13201110002222 is a deficient number, since it is larger than the sum of its proper divisors (6600555001114).

13201110002222 is an equidigital number, since it uses as much as digits as its factorization.

13201110002222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6600555001113.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 13201110002222 its reverse (22220001110231), we get a palindrome (35421111112453).

The spelling of 13201110002222 in words is "thirteen trillion, two hundred one billion, one hundred ten million, two thousand, two hundred twenty-two".

Divisors: 1 2 6600555001111 13201110002222