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132011210312027 is a prime number
BaseRepresentation
bin11110000001000001000001…
…010011000000100101011011
3122022102011000020000222211122
4132001001001103000211123
5114300332424314441102
61144433040210515455
736543331566246134
oct3601010123004533
9568364006028748
10132011210312027
11390767047723a2
12129807a7295b8b
1358877b049ba87
14248553b826c8b
15103ddab80a0a2
hex7810414c095b

132011210312027 has 2 divisors, whose sum is σ = 132011210312028. Its totient is φ = 132011210312026.

The previous prime is 132011210311909. The next prime is 132011210312029. The reversal of 132011210312027 is 720213012110231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132011210312027 - 216 = 132011210246491 is a prime.

Together with 132011210312029, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 132011210311987 and 132011210312005.

It is not a weakly prime, because it can be changed into another prime (132011210312029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66005605156013 + 66005605156014.

It is an arithmetic number, because the mean of its divisors is an integer number (66005605156014).

Almost surely, 2132011210312027 is an apocalyptic number.

132011210312027 is a deficient number, since it is larger than the sum of its proper divisors (1).

132011210312027 is an equidigital number, since it uses as much as digits as its factorization.

132011210312027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 132011210312027 its reverse (720213012110231), we get a palindrome (852224222422258).

The spelling of 132011210312027 in words is "one hundred thirty-two trillion, eleven billion, two hundred ten million, three hundred twelve thousand, twenty-seven".