Base | Representation |
---|---|
bin | 1100000000011010000001… |
… | …0100011000111010101000 |
3 | 1201202000102001011111101210 |
4 | 3000012200110120322220 |
5 | 3212241400243400404 |
6 | 44024302430113120 |
7 | 2531515110162621 |
oct | 300064024307250 |
9 | 51660361144353 |
10 | 13201124200104 |
11 | 422a624505095 |
12 | 159257194b7a0 |
13 | 749b25b7c349 |
14 | 338d1b544a48 |
15 | 17d5d1672689 |
hex | c01a0518ea8 |
13201124200104 has 64 divisors (see below), whose sum is σ = 33421741056000. Its totient is φ = 4344521238720.
The previous prime is 13201124200097. The next prime is 13201124200109. The reversal of 13201124200104 is 40100242110231.
It is a super-2 number, since 2×132011242001042 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13201124200109) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 62293477 + ... + 62505035.
It is an arithmetic number, because the mean of its divisors is an integer number (522214704000).
Almost surely, 213201124200104 is an apocalyptic number.
It is an amenable number.
13201124200104 is an abundant number, since it is smaller than the sum of its proper divisors (20220616855896).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13201124200104 is a wasteful number, since it uses less digits than its factorization.
13201124200104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 244558 (or 244554 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 13201124200104 its reverse (40100242110231), we get a palindrome (53301366310335).
The spelling of 13201124200104 in words is "thirteen trillion, two hundred one billion, one hundred twenty-four million, two hundred thousand, one hundred four".
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