1320113 has 2 divisors, whose sum is σ = 1320114. Its totient is φ = 1320112.

The previous prime is 1320107. The next prime is 1320119. The reversal of 1320113 is 3110231.

It is a balanced prime because it is at equal distance from previous prime (1320107) and next prime (1320119).

It can be written as a sum of positive squares in only one way, i.e., 1317904 + 2209 = 1148^2 + 47^2 .

It is an emirp because it is prime and its reverse (3110231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1320113 - 2¹² = 1316017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is equal to p₁₀₁₄₄₁ and since 1320113 and 101441 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 1320094 and 1320103.

It is not a weakly prime, because it can be changed into another prime (1320119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660056 + 660057.

It is an arithmetic number, because the mean of its divisors is an integer number (660057).

2^1320113 is an apocalyptic number.

It is an amenable number.

1320113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320113 is an equidigital number, since it uses as much as digits as its factorization.

1320113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 1320113 is about 1148.9617051930. The cubic root of 1320113 is about 109.6992611772.

Adding to 1320113 its reverse (3110231), we get a palindrome (4430344).

The spelling of 1320113 in words is "one million, three hundred twenty thousand, one hundred thirteen".