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13201140315431 is a prime number
BaseRepresentation
bin1100000000011010000101…
…0001110111010100100111
31201202000110011111020110202
43000012201101313110213
53212241413410043211
644024304203341115
72531515364152235
oct300064121672447
951660404436422
1013201140315431
11422a632611842
12159257722179b
13749b29302543
14338d1d73b955
1517d5d2ca753b
hexc01a1477527

13201140315431 has 2 divisors, whose sum is σ = 13201140315432. Its totient is φ = 13201140315430.

The previous prime is 13201140315379. The next prime is 13201140315439. The reversal of 13201140315431 is 13451304110231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13201140315431 - 214 = 13201140299047 is a prime.

It is a super-2 number, since 2×132011403154312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13201140315394 and 13201140315403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201140315439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600570157715 + 6600570157716.

It is an arithmetic number, because the mean of its divisors is an integer number (6600570157716).

Almost surely, 213201140315431 is an apocalyptic number.

13201140315431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201140315431 is an equidigital number, since it uses as much as digits as its factorization.

13201140315431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 13201140315431 its reverse (13451304110231), we get a palindrome (26652444425662).

The spelling of 13201140315431 in words is "thirteen trillion, two hundred one billion, one hundred forty million, three hundred fifteen thousand, four hundred thirty-one".