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1320120000317 is a prime number
BaseRepresentation
bin10011001101011101010…
…010001001111100111101
311200012110102200100222002
4103031131102021330331
5133112101210002232
62450242121032045
7164242542600416
oct23153522117475
94605412610862
101320120000317
11469950363228
12193a21625625
13976435c9181
1447c7378a80d
1524515496b62
hex1335d489f3d

1320120000317 has 2 divisors, whose sum is σ = 1320120000318. Its totient is φ = 1320120000316.

The previous prime is 1320120000301. The next prime is 1320120000383. The reversal of 1320120000317 is 7130000210231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1022826799801 + 297293200516 = 1011349^2 + 545246^2 .

It is an emirp because it is prime and its reverse (7130000210231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1320120000317 - 24 = 1320120000301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320120005317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660060000158 + 660060000159.

It is an arithmetic number, because the mean of its divisors is an integer number (660060000159).

Almost surely, 21320120000317 is an apocalyptic number.

It is an amenable number.

1320120000317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320120000317 is an equidigital number, since it uses as much as digits as its factorization.

1320120000317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 1320120000317 its reverse (7130000210231), we get a palindrome (8450120210548).

The spelling of 1320120000317 in words is "one trillion, three hundred twenty billion, one hundred twenty million, three hundred seventeen", and thus it is an aban number.