Base | Representation |
---|---|
bin | 11110000001000001110001… |
… | …100101000010001000101100 |
3 | 122022102020002200020211220101 |
4 | 132001001301211002020230 |
5 | 114300341104201441330 |
6 | 1144433252424400444 |
7 | 36543360633352354 |
oct | 3601016145021054 |
9 | 568366080224811 |
10 | 132012020343340 |
11 | 39076a8aa34965 |
12 | 12980992616124 |
13 | 58878ac254847 |
14 | 24855b7243b64 |
15 | 103de079b44ca |
hex | 78107194222c |
132012020343340 has 48 divisors (see below), whose sum is σ = 288226755210240. Its totient is φ = 50733791029440.
The previous prime is 132012020343331. The next prime is 132012020343353. The reversal of 132012020343340 is 43343020210231.
It is a happy number.
It is a super-2 number, since 2×1320120203433402 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132012020343299 and 132012020343308.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 765822502 + ... + 765994861.
It is an arithmetic number, because the mean of its divisors is an integer number (6004724066880).
Almost surely, 2132012020343340 is an apocalyptic number.
132012020343340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
132012020343340 is an abundant number, since it is smaller than the sum of its proper divisors (156214734866900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132012020343340 is a wasteful number, since it uses less digits than its factorization.
132012020343340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1531817542 (or 1531817540 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 132012020343340 its reverse (43343020210231), we get a palindrome (175355040553571).
The spelling of 132012020343340 in words is "one hundred thirty-two trillion, twelve billion, twenty million, three hundred forty-three thousand, three hundred forty".
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