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132012209005981 is a prime number
BaseRepresentation
bin11110000001000001111100…
…110100101110010110011101
3122022102020120211020220101121
4132001001330310232112131
5114300342001001142411
61144433323244210541
736543365414100253
oct3601017464562635
9568366524226347
10132012209005981
11390770774839a7
1212980a25839a51
13588790c36c645
1424855d43145d3
15103de1932e571
hex78107cd2e59d

132012209005981 has 2 divisors, whose sum is σ = 132012209005982. Its totient is φ = 132012209005980.

The previous prime is 132012209005949. The next prime is 132012209005997. The reversal of 132012209005981 is 189500902210231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71705584447225 + 60306624558756 = 8467915^2 + 7765734^2 .

It is a cyclic number.

It is not a de Polignac number, because 132012209005981 - 25 = 132012209005949 is a prime.

It is a super-2 number, since 2×1320122090059812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132012209005181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006104502990 + 66006104502991.

It is an arithmetic number, because the mean of its divisors is an integer number (66006104502991).

Almost surely, 2132012209005981 is an apocalyptic number.

It is an amenable number.

132012209005981 is a deficient number, since it is larger than the sum of its proper divisors (1).

132012209005981 is an equidigital number, since it uses as much as digits as its factorization.

132012209005981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 43.

The spelling of 132012209005981 in words is "one hundred thirty-two trillion, twelve billion, two hundred nine million, five thousand, nine hundred eighty-one".