Base | Representation |
---|---|
bin | 1100000000011010011000… |
… | …0110110011110000100011 |
3 | 1201202000122210212211222121 |
4 | 3000012212012303300203 |
5 | 3212242100123201311 |
6 | 44024320215245111 |
7 | 2531520366431455 |
oct | 300064606636043 |
9 | 51660583784877 |
10 | 13201221303331 |
11 | 422a6742a8196 |
12 | 159259a379797 |
13 | 749b4001a489 |
14 | 338d2a3c02d5 |
15 | 17d5d9e53b71 |
hex | c01a61b3c23 |
13201221303331 has 2 divisors, whose sum is σ = 13201221303332. Its totient is φ = 13201221303330.
The previous prime is 13201221303253. The next prime is 13201221303379. The reversal of 13201221303331 is 13330312210231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13201221303331 - 215 = 13201221270563 is a prime.
It is a super-2 number, since 2×132012213033312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13201221303296 and 13201221303305.
It is not a weakly prime, because it can be changed into another prime (13201221306331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600610651665 + 6600610651666.
It is an arithmetic number, because the mean of its divisors is an integer number (6600610651666).
Almost surely, 213201221303331 is an apocalyptic number.
13201221303331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201221303331 is an equidigital number, since it uses as much as digits as its factorization.
13201221303331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13201221303331 its reverse (13330312210231), we get a palindrome (26531533513562).
The spelling of 13201221303331 in words is "thirteen trillion, two hundred one billion, two hundred twenty-one million, three hundred three thousand, three hundred thirty-one".
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