Base | Representation |
---|---|
bin | 11000100101101101… |
… | …01111110001110011 |
3 | 1021002000110122022020 |
4 | 30102312233301303 |
5 | 204014004241001 |
6 | 10021540242523 |
7 | 645065500440 |
oct | 142266576163 |
9 | 37060418266 |
10 | 13201243251 |
11 | 5664837499 |
12 | 26850a0443 |
13 | 1324ca2b51 |
14 | 8d33929c7 |
15 | 523e54736 |
hex | 312dafc73 |
13201243251 has 32 divisors (see below), whose sum is σ = 20620976640. Its totient is φ = 7354900224.
The previous prime is 13201243177. The next prime is 13201243271. The reversal of 13201243251 is 15234210231.
It is not a de Polignac number, because 13201243251 - 211 = 13201241203 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13201243271) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 500961 + ... + 526653.
It is an arithmetic number, because the mean of its divisors is an integer number (644405520).
Almost surely, 213201243251 is an apocalyptic number.
13201243251 is a deficient number, since it is larger than the sum of its proper divisors (7419733389).
13201243251 is a wasteful number, since it uses less digits than its factorization.
13201243251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26315.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 13201243251 its reverse (15234210231), we get a palindrome (28435453482).
The spelling of 13201243251 in words is "thirteen billion, two hundred one million, two hundred forty-three thousand, two hundred fifty-one".
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