Base | Representation |
---|---|
bin | 11000100101101101… |
… | …11110011010111111 |
3 | 1021002000120200120201 |
4 | 30102312332122333 |
5 | 204014013200411 |
6 | 10021541424331 |
7 | 645066140344 |
oct | 142266763277 |
9 | 37060520521 |
10 | 13201303231 |
11 | 5664878566 |
12 | 268510b0a7 |
13 | 1324cc423c |
14 | 8d33aa7cb |
15 | 523e673c1 |
hex | 312dbe6bf |
13201303231 has 2 divisors, whose sum is σ = 13201303232. Its totient is φ = 13201303230.
The previous prime is 13201303201. The next prime is 13201303253. The reversal of 13201303231 is 13230310231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13201303231 - 27 = 13201303103 is a prime.
It is a super-2 number, since 2×132013032312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13201303199 and 13201303208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201303201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600651615 + 6600651616.
It is an arithmetic number, because the mean of its divisors is an integer number (6600651616).
Almost surely, 213201303231 is an apocalyptic number.
13201303231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201303231 is an equidigital number, since it uses as much as digits as its factorization.
13201303231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13201303231 its reverse (13230310231), we get a palindrome (26431613462).
The spelling of 13201303231 in words is "thirteen billion, two hundred one million, three hundred three thousand, two hundred thirty-one".
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