Base | Representation |
---|---|
bin | 10011001101011101111… |
… | …100100111010000111111 |
3 | 11200012111012121211121112 |
4 | 103031131330213100333 |
5 | 133112112032133211 |
6 | 2450243155352235 |
7 | 164243036314631 |
oct | 23153574472077 |
9 | 4605435554545 |
10 | 1320131130431 |
11 | 469956675473 |
12 | 193a252b267b |
13 | 976459c5239 |
14 | 47c75046a51 |
15 | 2451644488b |
hex | 1335df2743f |
1320131130431 has 2 divisors, whose sum is σ = 1320131130432. Its totient is φ = 1320131130430.
The previous prime is 1320131130427. The next prime is 1320131130457. The reversal of 1320131130431 is 1340311310231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1320131130431 - 22 = 1320131130427 is a prime.
It is a super-2 number, since 2×13201311304312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1320131130397 and 1320131130406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320131130421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660065565215 + 660065565216.
It is an arithmetic number, because the mean of its divisors is an integer number (660065565216).
Almost surely, 21320131130431 is an apocalyptic number.
1320131130431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320131130431 is an equidigital number, since it uses as much as digits as its factorization.
1320131130431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1320131130431 its reverse (1340311310231), we get a palindrome (2660442440662).
The spelling of 1320131130431 in words is "one trillion, three hundred twenty billion, one hundred thirty-one million, one hundred thirty thousand, four hundred thirty-one".
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