Base | Representation |
---|---|
bin | 1100000000011010101110… |
… | …0001001111110100100011 |
3 | 1201202000220010202211011121 |
4 | 3000012223201033310203 |
5 | 3212242241400320344 |
6 | 44024333221553111 |
7 | 2531522551365415 |
oct | 300065341176443 |
9 | 51660803684147 |
10 | 13201312120099 |
11 | 422a710597174 |
12 | 1592604875797 |
13 | 749b55a970cc |
14 | 338d384a09b5 |
15 | 17d5e2de2684 |
hex | c01ab84fd23 |
13201312120099 has 2 divisors, whose sum is σ = 13201312120100. Its totient is φ = 13201312120098.
The previous prime is 13201312120063. The next prime is 13201312120103. The reversal of 13201312120099 is 99002121310231.
It is a strong prime.
It is an emirp because it is prime and its reverse (99002121310231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13201312120099 - 211 = 13201312118051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201312100099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600656060049 + 6600656060050.
It is an arithmetic number, because the mean of its divisors is an integer number (6600656060050).
Almost surely, 213201312120099 is an apocalyptic number.
13201312120099 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201312120099 is an equidigital number, since it uses as much as digits as its factorization.
13201312120099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 34.
The spelling of 13201312120099 in words is "thirteen trillion, two hundred one billion, three hundred twelve million, one hundred twenty thousand, ninety-nine".
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