Base | Representation |
---|---|
bin | 111101011110010011… |
… | …0001110010010100101 |
3 | 110121202020001010210101 |
4 | 1322330212032102211 |
5 | 4130330331433433 |
6 | 140351312024101 |
7 | 12352260210232 |
oct | 1727446162245 |
9 | 417666033711 |
10 | 132013155493 |
11 | 50a93a916aa |
12 | 21702b32031 |
13 | c5aaca6abb |
14 | 65649ca789 |
15 | 367997407d |
hex | 1ebc98e4a5 |
132013155493 has 2 divisors, whose sum is σ = 132013155494. Its totient is φ = 132013155492.
The previous prime is 132013155473. The next prime is 132013155511. The reversal of 132013155493 is 394551310231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131774082049 + 239073444 = 363007^2 + 15462^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132013155493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132013155473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006577746 + 66006577747.
It is an arithmetic number, because the mean of its divisors is an integer number (66006577747).
Almost surely, 2132013155493 is an apocalyptic number.
It is an amenable number.
132013155493 is a deficient number, since it is larger than the sum of its proper divisors (1).
132013155493 is an equidigital number, since it uses as much as digits as its factorization.
132013155493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 37.
The spelling of 132013155493 in words is "one hundred thirty-two billion, thirteen million, one hundred fifty-five thousand, four hundred ninety-three".
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