Base | Representation |
---|---|
bin | 11000100101101110… |
… | …00010110101001011 |
3 | 1021002000121121100121 |
4 | 30102313002311023 |
5 | 204014014240131 |
6 | 10021542044111 |
7 | 645066244114 |
oct | 142267026513 |
9 | 37060547317 |
10 | 13201321291 |
11 | 5664890094 |
12 | 2685119637 |
13 | 1324ccc522 |
14 | 8d33b320b |
15 | 523e6c911 |
hex | 312dc2d4b |
13201321291 has 2 divisors, whose sum is σ = 13201321292. Its totient is φ = 13201321290.
The previous prime is 13201321267. The next prime is 13201321351. The reversal of 13201321291 is 19212310231.
13201321291 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (19212310231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13201321291 - 29 = 13201320779 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201321261) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600660645 + 6600660646.
It is an arithmetic number, because the mean of its divisors is an integer number (6600660646).
Almost surely, 213201321291 is an apocalyptic number.
13201321291 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201321291 is an equidigital number, since it uses as much as digits as its factorization.
13201321291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 13201321291 in words is "thirteen billion, two hundred one million, three hundred twenty-one thousand, two hundred ninety-one".
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