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132013221311009 is a prime number
BaseRepresentation
bin11110000001000010111001…
…001010010111001000100001
3122022102100012101002022211102
4132001002321022113020201
5114300401034123423014
61144434011525324145
736543432455411003
oct3601027112271041
9568370171068742
10132013221311009
1139077546941725
1212981068866655
135887a40cc75bc
14248568c946373
15103de781418de
hex7810b9297221

132013221311009 has 2 divisors, whose sum is σ = 132013221311010. Its totient is φ = 132013221311008.

The previous prime is 132013221310979. The next prime is 132013221311011. The reversal of 132013221311009 is 900113122310231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110150377515025 + 21862843795984 = 10495255^2 + 4675772^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132013221311009 is a prime.

Together with 132013221311011, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132013221317009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006610655504 + 66006610655505.

It is an arithmetic number, because the mean of its divisors is an integer number (66006610655505).

Almost surely, 2132013221311009 is an apocalyptic number.

It is an amenable number.

132013221311009 is a deficient number, since it is larger than the sum of its proper divisors (1).

132013221311009 is an equidigital number, since it uses as much as digits as its factorization.

132013221311009 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

The spelling of 132013221311009 in words is "one hundred thirty-two trillion, thirteen billion, two hundred twenty-one million, three hundred eleven thousand, nine".