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1320132320134 = 21833973599111
BaseRepresentation
bin10011001101011110000…
…001001001101110000110
311200012111021212021120121
4103031132001021232012
5133112112333221014
62450243241052154
7164243052401305
oct23153601115606
94605437767517
101320132320134
114699573082a1
12193a2578705a
13976460208c4
1447c7527643c
15245165cc124
hex1335e049b86

1320132320134 has 8 divisors (see below), whose sum is σ = 1980209827728. Its totient is φ = 660062377560.

The previous prime is 1320132320053. The next prime is 1320132320179. The reversal of 1320132320134 is 4310232310231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 1320132320099 and 1320132320108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1432762 + ... + 2166349.

It is an arithmetic number, because the mean of its divisors is an integer number (247526228466).

Almost surely, 21320132320134 is an apocalyptic number.

1320132320134 is a deficient number, since it is larger than the sum of its proper divisors (660077507594).

1320132320134 is a wasteful number, since it uses less digits than its factorization.

1320132320134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3782510.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1320132320134 its reverse (4310232310231), we get a palindrome (5630364630365).

The spelling of 1320132320134 in words is "one trillion, three hundred twenty billion, one hundred thirty-two million, three hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 183397 366794 3599111 7198222 660066160067 1320132320134