Base | Representation |
---|---|
bin | 1100000000011010110011… |
… | …0010000010101100111111 |
3 | 1201202000221121121212120112 |
4 | 3000012230302002230333 |
5 | 3212242312311100111 |
6 | 44024335255540235 |
7 | 2531523226410452 |
oct | 300065462025477 |
9 | 51660847555515 |
10 | 13201333300031 |
11 | 422a721542a48 |
12 | 159260b98a67b |
13 | 749b5a2a1606 |
14 | 338d3b215499 |
15 | 17d5e4bc7e8b |
hex | c01acc82b3f |
13201333300031 has 2 divisors, whose sum is σ = 13201333300032. Its totient is φ = 13201333300030.
The previous prime is 13201333300027. The next prime is 13201333300037. The reversal of 13201333300031 is 13000333310231.
It is a weak prime.
It is an emirp because it is prime and its reverse (13000333310231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13201333300031 - 22 = 13201333300027 is a prime.
It is a super-2 number, since 2×132013333000312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13201333300037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600666650015 + 6600666650016.
It is an arithmetic number, because the mean of its divisors is an integer number (6600666650016).
Almost surely, 213201333300031 is an apocalyptic number.
13201333300031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201333300031 is an equidigital number, since it uses as much as digits as its factorization.
13201333300031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13201333300031 its reverse (13000333310231), we get a palindrome (26201666610262).
The spelling of 13201333300031 in words is "thirteen trillion, two hundred one billion, three hundred thirty-three million, three hundred thousand, thirty-one".
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