Base | Representation |
---|---|
bin | 11110000001000011101000… |
… | …110110001000100111101011 |
3 | 122022102102021010102202001202 |
4 | 132001003220312020213223 |
5 | 114300404203424040201 |
6 | 1144434223144234415 |
7 | 36543461341342211 |
oct | 3601035066104753 |
9 | 568372233382052 |
10 | 132014021315051 |
11 | 39077917485597 |
12 | 1298125076ba0b |
13 | 5887b3a97c285 |
14 | 2485726cb2cb1 |
15 | 103dec34b9c6b |
hex | 7810e8d889eb |
132014021315051 has 2 divisors, whose sum is σ = 132014021315052. Its totient is φ = 132014021315050.
The previous prime is 132014021315017. The next prime is 132014021315101. The reversal of 132014021315051 is 150513120410231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132014021315051 is a prime.
It is not a weakly prime, because it can be changed into another prime (132014021915051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66007010657525 + 66007010657526.
It is an arithmetic number, because the mean of its divisors is an integer number (66007010657526).
Almost surely, 2132014021315051 is an apocalyptic number.
132014021315051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132014021315051 is an equidigital number, since it uses as much as digits as its factorization.
132014021315051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 132014021315051 its reverse (150513120410231), we get a palindrome (282527141725282).
The spelling of 132014021315051 in words is "one hundred thirty-two trillion, fourteen billion, twenty-one million, three hundred fifteen thousand, fifty-one".
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